I have to say that I always considered the ability to unlock BlackBerrys as a black art. I know very little about how it is done and assumed ninjas broke into RIM secret underground bunker and stole the codes (I’m kidding) On the other hand I got a bit of insight today from B1620N on how some companies are firmware flashing these BlackBerrys. I cannot say who uses this solution but I did not believe this was possible! I would not believe it unless I got it from a trusted source that it works.
Furious Gold seems to be based on a tool that leaked from RIM (MMLMultiLoader) a bit back that we are not allowed to talk about. The downside to this method is that it only works when the device is connected to the computer with the software so I am not sure how remote unlocking works. It also costs a pretty penny as you can see on the Furious Gold website. (~189-300 Euro)
Describing this tool is one of those situations where a picture is worth a 1000 words…
Yeah you saw that right! You can change the IMEI or ESN number along with clone another persons BlackBerry PIN!!! It also lets you set the MEP data allowing you to totally lock or unlock a BlackBerry. On top of that it lets you clear the branding!!! It works on practically all BlackBerry devices including the newer ones.
This tool also allows you to turn a BlackBerry into a Engineering Unit or EU for short. That means it does not require signed code to run it. This is big for developers who do not want to have to sign code every time they are testing a new application version. The crazy part is that people now have the ability to change their PIN & IMEI number! These are traditionally always tied to a device.
I can only imagine what will happen next… I always thought the PIN & IMEI were imprinted into the hardware of a BlackBerry. Now imagine somebody cloning Obama’s PIN… This might just be huge chink in the BlackBerry’s security armor. The one saving grace is that the application is expensive and a bit hard to find out exactly which package you need.
So what do you think?